For the moon to cease to remain the earth's satellite its orbital velocity has to increase by a factor of

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\sqrt{2}

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1 \sqrt{2}

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\sqrt{3}

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Solution

The correct option is B $\sqrt{2}$

We know that $v_{e} = \sqrt{2} v_{0},$
i.e. If the orbital velocity of moon is increased by factor of $\sqrt{2}$
then it will escape out from the gravitational field of earth.
Hence,
Option $B$ is correct answer.

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For the moon to cease to remain the earth's satellite its orbital velocity has to increase by a factor of

The correct option is B √2We know that ve=√2v0,i.e. If the orbital velocity of moon is increased by factor of √2then it will escape out from the gravitational field of earth.Hence,Option B is correct answer.

The correct option is B $\sqrt{2}$

We know that $v_{e} = \sqrt{2} v_{0},$
i.e. If the orbital velocity of moon is increased by factor of $\sqrt{2}$
then it will escape out from the gravitational field of earth.
Hence,
Option $B$ is correct answer.