For the MOSFET configuration given below it is given W/L = 2, $V_{D D} = 2 V, μ_{n} C_{o x} = 100 μ A / V^{2}$ and $V_{T h} = 0.5 V$ . The mode of operation of MOSFET switches from saturation region to linear region when value $V_{G S}$ will be______ V. (Answer upto 2 decimal places)

1.5

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Solution

The correct option is A 1.5
For saturation,

$I_{D} = K_{n} (V_{G S} - V_{t})^{2}$

$I_{D} = \frac{μ_{n} C_{o x}}{2} \frac{W}{L} (V_{G S} - V_{t})^{2}$

$= \frac{1}{2} \times 100 \times 10^{- 6} \times 2 (V_{0})^{2}$

By applying KVL in outer loop,

$V_{D D} = I_{D} \times 10 k Ω + V_{0}$

$2 = 100 \times 10^{- 6} V_{0}^{2} \times 10^{4} + V_{0}$

$0 = V_{0}^{2} + V_{0} - 2$

$∴$ $V_{0} = 1 V$

$V_{D S} = V_{G S} - V_{T h}$

$V_{0} = V_{i n} - V_{T h}$

$∴$ $V_{i n} = V_{G S} = V_{0} + V_{T h} = 1 + 0.5 = 1.5 V$

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A n i d e a l n - c h a n n e l M O S F E T h a s t h e f o l l o w i n g p a r a m e t e r s, t h r e s h o l d v o l t a g e V_{T} = 0.65 V a n d o x i d e t h i c k n e s s i s 0.4 n m . I t i s f o u n d t h a t t h e M O S F E T o p e r a t i n g i n s a t u r a t i o n r e g i o n w i t h V_{D S} = 6 V . T h e n t h e p o w e r d i s s i p a t i o n i n t h e M O S F E T w i t h V_{G S} = 4 V i s μ_{n} C_{a x} \frac{W}{L} = 1.5 \times 10^{- 3} A / V^{2},

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