For the network of resistance shown in the figure the equivalent resistance of the network between the points A and B is 18ohm. The value of unknown resistance R is :-
A
8Ω
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B
10Ω
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C
16Ω
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D
24Ω
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Solution
The correct option is C16Ω The equivalent circuit is shown in figure. here, Req1=10×1010+10=5Ω, Req2=5+10=15Ω, Req3=15×1015+10=6Ω Thus, RAB=R||(10+6)+10=16R16+R+10 or 18=16R16+R+10 or 8=16R16+R or 16+R=2R⇒R=16Ω