wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For the network shown in the figure, the value of the current i is


A
9V35
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5V18
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
5V9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
18V5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 5V18
This arrangement can be modified as shown in figure.


We can clearly see that the given circuit is balanced Wheatstone bridge and no current flows through 4 Ω resistance connected across the diagonal.

Now circuit reduces to


So, equivalent resistance of circuit will be

Req=6×96+9=185 Ω

Current will be

i=VR=V18/5=5V18

Hence, option (b) is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon