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Question
For the non-equilibrium process, A+B→Products the rate is first order with respect to A and second order with respect to B. If 1.0 mole each of A and B are introduced into 1 litre vessel, and the initial rate were 1.0×10−2 mil. litre-sec, the rate when half of the reactants have been used:
For the non-equilibrium process, A+B→Products the rate is first order with respect to A and second order with respect to B. If 1.0 mole each of A and B are introduced into 1 litre vessel, and the initial rate were 1.0×10−2 mil. litre-sec, the rate when half of the reactants have been used:
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Solution
The correct option is B 1.25×10−3mollitre−1sec−1
Rate=K[A][B]2
∴10−2=K[1][1]2
or K=10−2litre2mol−2sec−1
Now, rateII=10−2×0.5×(0.5)2
or New rate =1.25×10−3mollitre−1sec−1
Rate=K[A][B]2
∴10−2=K[1][1]2
or K=10−2litre2mol−2sec−1
Now, rateII=10−2×0.5×(0.5)2
or New rate =1.25×10−3mollitre−1sec−1
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