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Question

For the non - stoichiometric reaction, 2A+B C + D, the following kinetic data were obtained in three separate experiments, all at 298 K.

InitialInitialInitial rate of concentrationconcentrationformation of C [A][B](mol L1s1)(i)0.1 M0.1 M1.2×103(ii)0.1 M0.2 M1.2×13(iii)0.2 M0.1 M2.4×103

The rate law for the formation of C is


A

dCdt=k[A][B]

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B

dCdt=k[A]2[B]

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C

dCdt=k[A][B]2

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D

dCdt=k[A]

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Solution

The correct option is D

dCdt=k[A]


This problem can be solved by determining the order of reaction w.r.t each reactant and then writing rate law equation of the given equation accordingly as

R=dCdt=k[A]x[B]y

where,
x = order of reaction w.r.t A
y = order of reaction w.r.t B

1.2×103=k(0.1)x(0.1)y
1.2×103=k(0.1)x(0.2)y .....Doubling [B] had no impact on rate.This implies that change in [B] does not affect the rate. So, order w.r.t [B] is 0
2.4×103=k(0.2)x(0.1)y...... Doubling [A] doubled the rate.This implies that change in [A] affects the rate linearly. So, order w.r.t [A] is 1

R=k[A]1[B]0 is the rate law for the given reaction.

dCdt=k[A]


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