For the parabola $9 x^{2} - 24 x y + 16 y^{2} - 20 x - 15 y - 60 = 0$ which of the following is/ are true.

f o c u s = (- \frac{43}{25}, - \frac{129}{100})

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f o c u s = (\frac{43}{25}, \frac{129}{100})

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d i r e c t r i x : 4 x + 3 y + \frac{53}{4} = 0

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d i r e c t r i x : 4 x + 3 y - \frac{53}{4} = 0

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Solution

The correct options are
B $f o c u s = (\frac{43}{25}, \frac{129}{100})$
C $d i r e c t r i x : 4 x + 3 y + \frac{53}{4} = 0$

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