Let the arithmetic sequence is 68,x,54.
For an arithmetic sequence, we know that the next term is formed by adding a constant value to its preceding term.
Let's say the constant term is d.
∴x=68+d ..(a)
Again, 54=x+d ...(b)
Now solve these simultaneous equations.
From (b) d=54−x
Substitute d in (a)
x=68+54−x
⇒2x=122
⇒x=61
The sequence is 68,61,54.