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Standard XII

Mathematics

Slope of a Line Connecting Two Points

For the point...

Question

For the points $A (5, 0)$ and $B (7, 3)$ , calculate the angle between $A B$ and the $x -$ axis.

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Solution

The slope of the line (AB) is:
$m = \frac{(y_{B} - y_{A})}{(x_{B} - x_{A})} = \frac{(3 - 0)}{(7 - 5)} = \frac{3}{2}$
…and the slope represents the tangent of the line (AB)
The angle $α$ is such as:
$tan (α) = \frac{3}{2}$
or, $α = {56.31}^{o}$ .

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For the points A(5,0) and B(7,3), calculate the angle between AB and the x−axis.

The slope of the line (AB) is: m=(yB−yA)(xB−xA)=(3−0)(7−5)=32…and the slope represents the tangent of the line (AB) The angle α is such as: tan(α)=32or, α=56.31o.

For the points $A (5, 0)$ and $B (7, 3)$ , calculate the angle between $A B$ and the $x -$ axis.

The slope of the line (AB) is:
$m = \frac{(y_{B} - y_{A})}{(x_{B} - x_{A})} = \frac{(3 - 0)}{(7 - 5)} = \frac{3}{2}$
…and the slope represents the tangent of the line (AB)
The angle $α$ is such as:
$tan (α) = \frac{3}{2}$
or, $α = {56.31}^{o}$ .