Question

For the portal frame shown in the given figure, the shear equation is

• A. $\frac{M_{BA}+M_{AB}}{4}+\frac{M_{CD}}{4}+P=0$
• B. $\frac{M_{BC}+M_{CB}}{4}+P=0$
• C. $\frac{M_{CD}}{4}+P=0$
• D. $\frac{M_{BA}+M_{AB}}{4}+P=0$

Answer 1

The correct option is A $\frac{M_{BA}+M_{AB}}{4}+\frac{M_{CD}}{4}+P=0$

$\text{Shear in column AB}=\frac{M_{AB}+M_{BA}}{4}$

$\text{Shear in column CD}=\frac{M_{CD}}{4}$

Shear equation will be

$\frac{M_{AB}+M_{BA}}{4}+\frac{M_{CD}}{4}+P=0$