For the preparation of n-propyl bromide from n-propyl alcohol, which is the following reagent is most preferred?

P_{4} / B r_{2}

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H B r

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B r_{2}

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N a B r

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Solution

The correct option is B $H B r$
Ans : B $\to$ $H B r$
$n -$ propyl alcohol is converted to $n -$ propyl bromide by treating it with hydrobromic acid.

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