For the process $H_{2} O (l) (1 b a r, 373 K) \to H_{2} O (g) (1 b a r, 373 K)$ , the correct set of thermodynamic parameters is

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Solution

The correct option is A

Since, liquid is passing into gaseous phase so entropy will increase and at 373 K during the phase transformation it remains at equilibrium. So, $Δ G = 0$

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Similar questions

For $H_{2} O (l) (1 b a r, 373 K) \to H_{2} O (g) (1 b a r, 373 K)$ .The correct set of thermodynamic parameter is

H_{2} O (l) (1 bar, 373 K) ⇌ H_{2} O (g) (1 bar, 373 K)

H_{2} O (l) (1 b a r, 373 K) ⇌ H_{2} O (g) (1 b a r, 373 K)

H_{2} O (l) ⇌ H_{2} O (g) (1 b a r, 373 K),

H_{2} O_{(l)} (1 bar, 373 K) ⇌ H_{2} O_{(g)} (1 bar, 373 K)

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