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Question

For the process
H2O (l)H2O (g) (1 atm, 373K), the correct set of thermodynamic parameters is

A
G=0,S=+ve
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B
G=0,S=ve
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C
G=+ve,S=0
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D
G=ve,S=+ve
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Solution

The correct option is A G=0,S=+ve
At 373 K, H2O(l) is in equilibrium with H2O(g), and for an equilibrium process we know change in gibbs free energy is zero,
therefore G=0.

As liquid phase changes to gaseous phase, molecules entropy increases, therefore S=+ve .

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