The correct option is A ΔG=0, ΔS=+ve
H2O(l)(1 bar, 373 K)⇌H2O(g)(1 bar, 373 K)
At 100 ∘C, H2O(l) is in equilibrium with H2O(g) therefore, ΔG=0. Because liquid molecules are converting into gaseous molecules, therefore randomness increases and hence, ΔS=+ve