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Question

For the reaction 2NO2N2O2+O2, rate expression is as follows;
d[NO2]dt=k[NO2]n, where k=3×103mol1Lsec1. If the rate of formation of oxygen is 1.5×104molL1sec1, then the molar concentration of NO2 in mole L1 is:

A
1.5×104
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B
0.0151
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C
0.214
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D
0.316
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Solution

The correct option is D 0.316
2NO2N2O2+O2
d[NO2]dt=k[NO2]n
k=3×103mol1Lsec1.........(1)
SI unit for k is (molL1)
From (1)
1order=1
order=2
d[NO2]dt=k[NO2]2
d[u2]dt=12d[NO2]dt
1.5×104=k2[NO2]2
1.5×104=32×103×[NO2]2
101=[NO2]2
[NO2]=110
=0.316 mol/L

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