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Question

For the reaction 2A + 3B products, A is in excess and on changing the concentration of B from 0.1 M to 0.4 M, rate becomes doubled. Thus, rate law is

A
dxdt=k[A]2[B]2
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B
dxdt=k[A][B]
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C
dxdt=k[A]0[B]2
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D
dxdt=k[B]1/2
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