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Question

For the reaction:
2A(g)+B(g)2D(g),

ΔU=10.5 kJ and ΔS=44.1 JK1.Does the reaction occur spontaneously?
[Give your answer in terms of Yes or No]

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Solution

Given:-
ΔU0=10.5kJ
ΔS0=44.1J/K
2A(g)+B(g)2D(g)

For the above reaction-
Δng=2(2+1)=1

As we know that,
ΔH0=ΔU0+ΔngRT
ΔH0=10.5+(1×8.314×103)(298)
ΔH0=12.98kJ

Again as we know that,
ΔG0=ΔH0TΔS0
ΔG0=12.98298×(44.1×103)=+0.16kJ

Since ΔG0 for the reaction is positive, the reaction will not occur spontaneously.

Hence the correct answer is No.

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