Question

For the reaction $2A⟶B+3C$; if $-\frac{d\left[A\right]}{dt}=k_1{\left[A\right]}^2;\frac{d\left[B\right]}{dt}=k_2{\left[B\right]}^2;\frac{d\left[A\right]}{dt}=k_3{\left[A\right]}^2$ the correct relation between $k_1,k_2$ and $k_3$

• A. $k_1=k_2=k_3$
• B. $2k_1=k_2=3k_3$
• C. $4k_1=k_2=3k_3$
• D. $\frac{k_1}{2}=k_2=\frac{k_3}{3}$

Answer 1

The correct option is D $\frac{k_1}{2}=k_2=\frac{k_3}{3}$

$\frac{1}{2}\frac{dA}{dt}=\frac{dA}{dt}\left[B\right]=\frac{1}{3}=\frac{d\left[C\right]}{dt}$

$\frac{k_1}{2}=k_2=\frac{k_3}{3}$