For the reaction- 2AgCls-H2g1atm- 2Ags-2H-0-1M-2Cl-0-1M- - Go-43600J at 25oC-Calculate the e-m-f of the cell- -log 10-n-n-

Δ G^o= nFE^0_cell 43600 = 2 × 96500 × E^0_cell E^0_cell=0.23V E_cell=E^0_cell 0.0591nlog_10[H^+]^2[Cl^ ]^2P_H2 E_cell=0.23V 0.05912lo ...

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For the react...

Question

For the reaction.
$2 A g C l (s) + H_{2} (g) (1 a t m) \to 2 A g (s) + 2 H^{+} (0.1 M) + 2 C l^{-} (0.1 M),$
$Δ G^{o} = - 43600$ J at $25^{o}$ C.
Calculate the e.m.f of the cell.
$[l o g 10^{- n} = - n]$ .

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2 A g C I (s) + H_{2} (g) (1 a t m) ⟶ 2 A g (s) + 2 H^{+} (0.1 M) + 2 C I^{-} (0.1 M),

Δ G^{\circ}

25^{\circ} C .

[l o g 10^{- n} = - n]

2 A g C I (s) + H_{2} (g) (1 a t m) ⟶ 2 A g (s) + 2 H^{+} (0.1 M) + 2 C I^{-} (0.1 M),

Δ G^{\circ}

25^{\circ} C .

[l o g 10^{- n} = - n]

Δ G^{0} = - 42927

25^{0} C

H_{2} (g, 1 a t m) + 2 A g C l (s) ⇌ 2 A g (s) + 2 H^{+} (a q, 0.1 M) + 2 C l^{-} (a q, 0.1 M)

Δ G^{o}

A g C l (s) + 1 / 2 H_{2} (g) ⟶ A g (s) + H^{+} + C l^{-}

- 21.52 k J

Δ G^{o}

2 A g C l (s) + H_{2} (g) \to 2 A g (s) + 2 H^{+} + 2 C l^{-}

Δ G^{\circ}

A g C l (s) + \frac{1}{2} H_{2} (g) \to A g (s) + H^{+} + C l^{-} is - 21.52 K J . Δ G^{\circ} of 2 A g C l (s) + H_{2} (g) \to 2 A g (s) + 2 H^{+} 2 C l^{-}

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