For the reaction, 2Cl(g)→Cl2(g), the signs of △H and △S respectively, are:
A
+,−
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B
+,+
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C
−,−
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D
−,+
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Solution
The correct option is B−,−
2Cl(g)→Cl2(g)
Atoms forming a molecule, making system less disordered. Entropy is decreasing ΔS(−ve) in the reaction. Further the addition reaction is exothermic since a bond is being formed, therefore ΔH is also −ve.