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Question

For the reaction,

2CO+O22CO2;ΔH=560KJ.

Two moles of CO and one mole of O2 are taken in a container of volume 1 L. They completely form two moles of CO2 the gases deviate appreciably from ideal behaviour. If the pressure in the vessel changes from 70 to 40 atm, then the magnitude (absolute value) of ΔU at 500 K is x kJ.

The value of 0.01x is ______(nearest integer).

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Solution

As we know,
ΔH=ΔU+Δ(PV)

Volume is constant.

ΔH=ΔU+VΔP

Substituting the given values,
ΔU=ΔH+VΔP

=560+1×30×0.1
=557 kJ

1 Latm=0.1 kJ

The value of 0.01x=5.576

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