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Question

For the reaction, 2Fe(NO3)3+3Na2CO3Fe2(CO3)3+6NaNO3
Initially if 2.5 mole of Fe(NO3)2 and 3.6 mole of Na2CO3 is taken. If 6.3 mole of NaNO3 is obtained then % yield of given reaction is:

A
50%
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B
84%
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C
87.5%
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D
100%
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Solution

The correct option is C 87.5%
Given reaction :
2Fe(NO3)3+3Na2CO3Fe2(CO3)3+6NaNO3
Therefore,
Two moles of Fe(NO3)3 reacts with three moles of Na2CO3
Therefore,
2.5 moles of Fe(NO3)3 reacts with 32×1.5=3.75 moles of Na2CO3
But 3.6 moles moles of Na2CO3 are given.
(It means that the same amount of Fe(NO3)3 will be nonreactive)
From the equation,
3 moles of Na2CO3 gives 6 moles of NaNO3
Therefore,
3.6 moles of Na2CO3 will give 7.2 moles of NaNO3
Hence,
% yield=experimentalyieldcalculatedyield
=6.37.2×100

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