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Question

For the reaction 2HI(g)H2(g)+I2(g) the degree of dissociation (α) of HI(g) is related to the equilibrium constant, Kpby expression.

A
1+2Kp2Kp
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B
1+2Kp2
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C
2Kp1+2Kp
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D
Kp1+2Kp
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Solution

The correct option is A Kp1+2Kp
2HI(g)H2(g)+I2(g)Initial:CEquilibrium:C(12α)CαCα
Where α= degree of dissociation.
Let Pt be total pressure,
PH2=xH2×P2=Cα×PtC2cα+Cα+Cα=α×Pt
PI2=CαC×Pt=αPt
PHI=C2CαC×Pt=(12α)Pt
KP=(PH2)(PI2)(PHI)2=α2×P2t(12α)2×P2t
α12α=KP
α=KP1+2KP

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