For the reaction- 2N2O5- 4NO2-O2 rate and rate constant are 2-40- 10-5 mol L-1s-1 and 3- 10-5s-1 respectively- then calculate the concentration of N2O5-

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Byju's Answer

Standard XII

Chemistry

Characteristics of Equilibrium Constant

For the react...

Question

For the reaction, $2 N_{2} O_{5} ⇌ 4 N O_{2} + O_{2}$ rate and rate constant are $2.40 \times 10^{- 5}$ mol $L^{- 1} s^{- 1}$ and $3 \times 10^{- 5} s^{- 1}$ respectively, then calculate the concentration of $N_{2} O_{5}$ .

1.4

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1.2

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0.04

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0.8

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Solution

The correct option is D $0.8$
The unit for the rate constant indicates that it is a first order reaction.
$r a t e = k [N_{2} O_{5}]$
$2.40 \times 10^{- 5} = 3 \times 10^{- 5} [N_{2} O_{5}]$
$[N_{2} O_{5}] = 0.8 M$

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Similar questions

Q. For the reaction,

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

rate and rate constant are

1.02 \times 10^{- 4} m o l L^{- 1} s^{- 1}

and

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respectively. The concentration of

N_{2} O_{5}

in mol

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will be:

Q. The rate constant for the reaction,

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

2 \times 10^{- 5} s^{- 1}

. If rate of reaction is

1.4 \times 10^{- 5} m o l L^{- 1} s^{- 1}

, what will be the concentration of

N_{2} O_{5}

in mol

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The rate constant for the first-order reaction, 2 $N_{2}$ $O_{5}$ $\to$ 4 ${N O}_{2}$ + $O_{2}$ is 3.0 $\times$ $10^{- 5}$ $s^{- 1}$ . If the rate is 2.40 $\times$ $10^{- 5}$ $\frac{m o l}{L}$ $s^{- 1}$ , then the initial concentration of $N_{2}$ $O_{5}$ (in $\frac{m o l}{L}$ ) is