For the reaction- 2N2O5- 4NO2-O2 rate and rate constant are 2-40- 10-5 mol L-1s-1 and 3- 10-5s-1 respectively- then calculate the concentration of N2O5-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Characteristics of Equilibrium Constant

For the react...

Question

For the reaction, $2 N_{2} O_{5} ⇌ 4 N O_{2} + O_{2}$ rate and rate constant are $2.40 \times 10^{- 5}$ mol $L^{- 1} s^{- 1}$ and $3 \times 10^{- 5} s^{- 1}$ respectively, then calculate the concentration of $N_{2} O_{5}$ .

1.4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.04

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.8

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $0.8$
The unit for the rate constant indicates that it is a first order reaction.
$r a t e = k [N_{2} O_{5}]$
$2.40 \times 10^{- 5} = 3 \times 10^{- 5} [N_{2} O_{5}]$
$[N_{2} O_{5}] = 0.8 M$

Suggest Corrections

Similar questions

Q. For the reaction,

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

rate and rate constant are

1.02 \times 10^{- 4} m o l L^{- 1} s^{- 1}

and

3.4 \times 10^{- 5} s^{- 1}

respectively. The concentration of

N_{2} O_{5}

in mol

L^{- 1}

will be:

Q. The rate constant for the reaction,

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

2 \times 10^{- 5} s^{- 1}

. If rate of reaction is

1.4 \times 10^{- 5} m o l L^{- 1} s^{- 1}

, what will be the concentration of

N_{2} O_{5}

in mol

L^{- 1}

The rate constant for the first-order reaction, 2 $N_{2}$ $O_{5}$ $\to$ 4 ${N O}_{2}$ + $O_{2}$ is 3.0 $\times$ $10^{- 5}$ $s^{- 1}$ . If the rate is 2.40 $\times$ $10^{- 5}$ $\frac{m o l}{L}$ $s^{- 1}$ , then the initial concentration of $N_{2}$ $O_{5}$ (in $\frac{m o l}{L}$ ) is