For the reaction 2NaN₃(s) → 2Na(s) + 3N₂ (g), how many moles of sodium azide (NaN₃) must react in order to produce 8.75 moles of nitrogen gas?

5.83 moles NaN₃

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13.1 moles NaN₃

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2.00 moles NaN₃

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2.50 moles NaN₃

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Solution

The correct option is A
5.83 moles NaN₃

3 moles of N₂are produced from 2 moles of NaN_3.

So, 8.75 moles of N₂are produced from 5.83 moles of NaN₃.

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