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Rate of Reaction

For the react...

Question

For the reaction :
$2 N H_{3} (g) \to N_{2} (g) + 3 H_{2} (g)$
if rate of disappearance of of $N H_{3}$ is $1.7 g m / s e c$ then rate of appearance of $N_{2}$ should be:

0.85 g m / s e c

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3.4 g m / s e c

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1.4 g m / s e c

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0.7 g m / s e c

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Solution

The correct option is A $0.85 g m / s e c$
${2 N H}_{3} (g) ⟶ N_{2} (g) + 3 H_{2} (g)$
Rate of disappearance of ${N H}_{3} = \frac{1}{2} \frac{d ({N H}_{3})}{d t}$
Rate of appearance of $N_{2} = \frac{d (N_{2})}{d t}$
$∴$ $\frac{1}{2} \frac{d ({N H}_{3})}{d t} = \frac{d (N_{2})}{d t}$
$∴$ $\frac{1.7 {g m s}^{- 1}}{2} = \frac{d (N_{2})}{d t}$
$∴$ $\frac{d (N_{2})}{d t} = 0.85 {g m s}^{- 1}$ .

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