For the reaction- 2NH3 - N2 - 3H2 - -NH3- t - K1 -NH3- - -N2- t - K2 -NH3- - -H2- t - K3 -NH3-Then relation between k1- k2 and k3 is-

The correct option is B 1.5k_1 = 3k_2 = k_3 1 2 [ NH _ 3 ] #160; t =[ N _ 2 ] #160; t = 1 3 [ H _ 2 ] #160; t log _ 2 ^ 8 =3 ...

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Characteristics of Equilibrium Constant

For the react...

Question

For the reaction, $2 N H_{3} \to N_{2} + 3 H_{2}$
$- \frac{Δ [N H_{3}]}{Δ t} = K_{1} [N H_{3}]; \frac{Δ [N_{2}]}{Δ t} = K_{2} [N H_{3}]; \frac{Δ [H_{2}]}{Δ t} = K_{3} [N H_{3}]$
Then relation between $k_{1}, k_{2}$ and $k_{3}$ is:

1.5 k_{1} = 3 k_{2} = k_{3}

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2 k_{1} = k_{2} = 3 k_{3}

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k_{1} = k_{2} = k_{3}

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k_{1} = 3 k_{2} = 2 k_{3}

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Solution

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2 N H_{3} \to N_{2} + 3 H_{2}

- \frac{d [N H_{3}]}{d t} = k_{1} [N H_{3}], \frac{d [N_{2}]}{d t} = k_{2} [N H_{3}], \frac{d [H_{2}]}{d t} = k_{3} [N H_{3}]

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2 N H_{3} ⟶ N_{2} + 3 H_{2}

\frac{- d [N H_{3}]}{d t} = k_{1} [N H_{3}], \frac{d [N_{2}]}{d t} = k_{2} [N H_{3}], \frac{d [H_{2}]}{d t} = k_{3} [N H_{3}]

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- \frac{Δ [N_{2} O_{5}]}{Δ t} = k_{1} [N_{2} O_{5}], + \frac{[N O_{2}]}{Δ t} = k_{2} [N_{2} O_{5}], + \frac{Δ [O_{2}]}{Δ t} = k_{3} [N_{2} O_{5}]

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25^{o}

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N_{2} + 3 H_{2} ⇌ 2 N H_{3}; K_{1}

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