For the reaction $2 N O_{2 (g)} ⇌ N_{2} O_{4 (g)}, K_{p} / K_{c}$ is equal to :

\frac{1}{R T}

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\sqrt{R T}

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(R T)^{2}

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Solution

The correct option is A $\frac{1}{R T}$
$2 N O_{2} (g) ⇌ N_{2} O_{4} (g)$
$Δ n$ is the number of moles of gaseous products - number of moles of gaseous reactants in a balanced reaction.
In the above reaction $Δ n = 1 - 2 = - 1.$
$K_{p} = K_{c} (R T)^{- 1}$
$∴ \frac{K_{p}}{K_{c}} = (R T)^{- 1} = \frac{1}{R T}$

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