Question

For the reaction $2\mathrm{P}+\mathrm{Q}=\mathrm{R}$, $8\mathrm{mol}$of P and $5\mathrm{mol}$of Q will produce

• A. $4\mathrm{mol}$ of R
• B. $5\mathrm{mol}$ of R
• C. $8\mathrm{mol}$ of R
• D. $13\mathrm{mol}$ of R

Answer 1

The correct option is A

$4\mathrm{mol}$ of R

The explanation for the correct answer:

Option (A) $4\mathrm{mol}$ of R

Step 1: Given Data

Mol of P$=8\mathrm{mol}$

Mol of R $=5\mathrm{mol}$

Given reaction $2\mathrm{P}+\mathrm{Q}=\mathrm{R}$

Step 2: Applying Stoichiometry

$2\mathrm{mol}$of P produces $1\mathrm{mol}$of R

So, $8\mathrm{mol}$ of P will produce $=\frac{1}{2}\times 8=4\mathrm{mol}$ of R

Therefore, $8\mathrm{mol}$of P and $5\mathrm{mol}$of Q produces $4\mathrm{mol}$of R.

Hence, option A is correct.