For the reaction 2X+Y2⟶2XYthe following mechanism has been given: X+Y2⇌XY2Keq(Equilibrium constant) XY2+X⟶2XY(slow)k(rate constant)
Order of the reaction is:
A
2
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B
0
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C
3
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D
1
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Solution
The correct option is C3 Expression of rate from slow step of reaction R=k[XY2][X].......(1) Keqb=[XY2][X][Y2].......(2)
from (1) and (2) R=k×Keq[X]2[Y2]
order of reaction is 3