For the reaction 3A ---->B+C k is 10^-4L/molmin if [A]=0.5M then the value of -d[A]/dt is

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3 A (g) k \to B (g) + C (g)

10^{- 4} L m o l^{- 1} m i n^{- 1}

\frac{- d [A]}{dt}

M s^{- 1}

3 A (g) k \to B (g) + C (g), k is 10^{- 14} L/mol~min

[A] = 0.5 M

- \frac{d [A]}{d t} (i n M s^{- 1})

3 A (g) k \to B (g) + C (g)

10^{- 4} L m o l^{- 1} m i n^{- 1}

\frac{- d [A]}{dt}

M s^{- 1}

2 A + B \to C + D, - \frac{d [A]}{d t} = k [A]^{2} [B]

\frac{- d [B]}{d t}

A + B \to p r o d u c t

\frac{d x}{d t} = k [A]^{a} [B]^{b}

\frac{d x}{d t} = k

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