Question

For the reaction
$3A\left(g\right)+B\left(g\right)\rightleftharpoons 2C\left(g\right)$
at a given temperature, $K_c$ is $9.0$. What must be the volume of a flask if the mixture of $2.0$ moles each of $A,B$ and $C$ is obtained at equilibrium?

Answer 1

Let V L is the volume of the flask.
$K_c=\frac{[C{]}^2}{\left[A{]}^3\right[B]}$
$9.0=\frac{(\frac{2.0mol}{VL}{)}^2}{(\frac{2.0mol}{VL}{)}^3\times (\frac{2.0mol}{VL})}$
$(\frac{2.0mol}{VL}{)}^2=\frac{1}{9.0}$
$\left(\frac{2.0mol}{VL}\right)=0.333$

$V=\frac{2.0}{0.333}=6$ L

The volume of the flask is 6 L.