For the reaction, 4C(graphite)+5H2⟶nC4H10;ΔHo=−124.73kJmol−1 4C(graphite)+5H2⟶iso−C4H10;ΔSo=−365.8JK−1mol−1 ΔHo=−131.6kJmol−1 ΔSo=−381.079JK−1mol−1 Indicate whether normal butane can be spontaneously converted to iso-butane or not.
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Solution
Yes, ΔGo=−2.32kJ For nC4H10 ΔGo=ΔHo−TΔSo =−15.72kJ For iso−C4H10 ΔGo=−18.04kJ For conversion ΔGo=−18.04−(−15.72)=−2.32kJ