For the reaction $4 N H_{3} + 5 O_{2} \to 4 N O + 6 H_{2} O,$ the rate of reaction with respect to $N H_{3}$ is $2 x 10^{- 3} M s^{- 1} .$ . Find the rate of the reaction with respect to oxygen in $M s^{- 1}$ .

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Solution

$4 N H_{3} + 50_{2} \to 4 N 0 + 6 n_{2} O$
or
$\frac{1}{4} \frac{d [N H_{3}]}{d t} = \frac{1}{5} \frac{d [O_{2}]}{O t}$
$\frac{d [o_{2}]}{d t} = \frac{5}{4} \frac{d [N H_{3}]}{d t}$
$\frac{5}{4} \times 2 \times 10^{- 3} M / S$
$= 2.5 \times 10^{- 3} M / S$

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For the reaction 4NH3+5O2→4NO+6H2O, the rate of reaction with respect to NH3 is 2x10−3Ms−1.. Find the rate of the reaction with respect to oxygen in Ms−1.

4NH3+502→4N0+6n2Oor 14d[NH3]dt=15d[O2]Otd[o2]dt=54d[NH3]dt54×2×10−3M/S=2.5×10−3M/S

For the reaction $4 N H_{3} + 5 O_{2} \to 4 N O + 6 H_{2} O,$ the rate of reaction with respect to $N H_{3}$ is $2 x 10^{- 3} M s^{- 1} .$ . Find the rate of the reaction with respect to oxygen in $M s^{- 1}$ .

$4 N H_{3} + 50_{2} \to 4 N 0 + 6 n_{2} O$
or
$\frac{1}{4} \frac{d [N H_{3}]}{d t} = \frac{1}{5} \frac{d [O_{2}]}{O t}$
$\frac{d [o_{2}]}{d t} = \frac{5}{4} \frac{d [N H_{3}]}{d t}$
$\frac{5}{4} \times 2 \times 10^{- 3} M / S$
$= 2.5 \times 10^{- 3} M / S$