For the reaction 4NH3-5O2 - 4NO-6H2O- the rate disappearance of ammonia is 3-6- 10-3 mol L-1s-1- What is the rate of formation of water -

From this Equation, The Rate can be written as #160; 14d[NH_3]dt = 16d[H_2O]dt Given , Rate of disappearance of NH_3 = 3.6 ×10^ 3molL^ 1 ...

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Standard XII

Chemistry

Rate of Reaction

For the react...

Question

For the reaction $4 N H_{3} + 5 O_{2} \to 4 N O + 6 H_{2} O$ , the rate disappearance of ammonia is $3.6 \times 10^{- 3}$ mol $L^{- 1} s^{- 1}$ . What is the rate of formation of water ?

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Solution

From this Equation, The Rate can be written as

$- \frac{1}{4} \frac{d [N H_{3}]}{d t}$ = $\frac{1}{6} \frac{d [H_{2} O]}{d t}$

Given , Rate of disappearance of $N H_{3}$ = $3.6 \times 10^{- 3} m o l L^{- 1} s^{- 1}$

$\frac{d [H_{2} O]}{d t}$ = $\frac{3}{2} \frac{d [N H_{3}]}{d t}$

$\frac{d [H_{2} O]}{d t}$ = $5.4 \times 10^{- 3} m o l L^{- 1} s^{- 1}$

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Similar questions

Q. For the reaction

{4 N H}_{3} + {5 O}_{2} ⟶ {4 N O + 6 H}_{2} O

, the rate of reaction with respect to

{N H}_{3}

{2 \times 10}^{- 3} {M s}^{- 1}

. Then the rate of the reaction with respect to oxygen is _____

{M s}^{- 1}

Q. Ammonia and oxygen react at high temperature as:

4 N H_{3} (g) + 5 O_{2} (g) \to 4 N O (g) + 6 H_{2} O (g)

In an experiment , the rate of formation of

N O

3.6 \times 10^{- 3} M s^{- 1}

. Calculate (a) the rate of disappearance of ammonia and (b) the rate of formation of water.

Ammonia and oxygen react at high temperature as:

4 N H_{3} (g) + 5 O_{2} (g) \to 4 N O (g) + 6 H_{2} O (g)

If rate of formation of NO is

3.6 \times 10^{- 3}

mol

L^{- 1}

s^{- 1}

then what will be the rate of formation of water?

For the reaction 4NH₃+5O₂ gives 4NO + 6H₂O, the rate of reaction with respect to NH₃ is 2*10^-3Ms^-1.Then the of the reaction with respect to oxygen is

Q. For the reaction

4 N H_{3} + 5 O_{2} \to 4 N O + 6 H_{2} O,

the rate of reaction with respect to

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2 x 10^{- 3} M s^{- 1} .

. Find the rate of the reaction with respect to oxygen in

M s^{- 1}

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For the reaction 4NH3+5O2→4NO+6H2O, the rate disappearance of ammonia is 3.6×10−3 mol L−1s−1. What is the rate of formation of water ?

From this Equation, The Rate can be written as −14d[NH3]dt = 16d[H2O]dtGiven , Rate of disappearance of NH3 = 3.6×10−3 molL−1s−1d[H2O]dt = 32d[NH3]dtd[H2O]dt = 5.4×10−3 molL−1s−1

For the reaction $4 N H_{3} + 5 O_{2} \to 4 N O + 6 H_{2} O$ , the rate disappearance of ammonia is $3.6 \times 10^{- 3}$ mol $L^{- 1} s^{- 1}$ . What is the rate of formation of water ?