Question

For the reaction: $7A+13B+15C\to 17P$
If 15 moles of A, 26 moles of B and 30.5 moles of C are taken initially, then the limiting reagent is:

• A. B
• B. A
• C. C
• D. None of these

Answer 1

The correct option is A B

As per stoichiometry, 7 mol of A will react with 13 mol of B and 15 mol of C
Finding the limiting reagent,
$\text{For A}=\frac{\text{given moles}}{\text{stoichiometric coefficient}}=\frac{15}{7}=2.14$
$\text{For B}=\frac{\text{given moles}}{\text{stoichiometric coefficient}}=\frac{26}{13}=2.00$
$\text{For C}=\frac{\text{given moles}}{\text{stoichiometric coefficient}}=\frac{30.5}{15}=2.03$
Since the ratio is the least for B, it will be the limiting reagent.