Question

For the reaction, $A+2B⟶C$, $5$ moles of $A$ and $8$ moles of $B$ will produce :

• A. $5$ moles of $C$
• B. $4$ moles of $C$
• C. $8$ moles of $C$
• D. $13$ moles of $C$

Answer 1

The correct option is B $4$ moles of $C$

The balanced chemical reaction is $A+2B⟶C$.
$5$ moles of $A$ will react with $\frac{5\times 2}{1}=10$ moles of $B$.
However, only $8$ moles of $B$ are present.
Thus, $B$ is the limiting reagent.
Hence, $8$ moles of B will give $\frac{8\times 1}{2}=4$ moles of $C$.