Question

For the reaction. $A+2B\to C$, 5 mole of $A$ and 8 mole of $B$ will produce:

• A. 5 mole of $C$
• B. 4 mole of $C$
• C. 8 mole of $C$
• D. 12 mole of $C$

Answer 1

The correct option is B 4 mole of $C$

Here $5$ moles of $A$ required $10$ moles of $B$ (As per stichometry)

So, $B$ is limiting reagent.

2 moles of $B$ gives 1 mole of $C$

Thus, $8$ moles of $B=4$ moles of $C$ is produced.

Hence, the correct option is $\text{B}.$