Question

For the reaction $A+2B\to C+D$ if active mass of $A$ is kept constant and active mass of $B$ is tripled. the rate of reaction will become:

• A. three times
• B. six times
• C. eight times
• D. nine times

Answer 1

The correct option is D nine times

Rate of reaction$\alpha$ $\left[A\right]\times [B{]}^2$

Now if the concentration of $A$ is kept constant and concentration of $B$ is tripled.

Then rate of reaction $\propto$ $\left[A\right]\times [3B{]}^2$

Therefore now taking the ratios we get that the rate of the reaction becomes $9$ times the initial