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Question

For the reaction, A+B Products, rate is given as, rate =k[A][B]2.
How will the rate change if volume of the reaction mixture is reduced to 1/3 of its original volume?

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Solution

When volume is reduced to 1/3rd, then concentration will increase three times.
r1=k[A][B]2 ...(i)
r2=k[3A][3B]2 ...(ii)
From equations (i) and (ii),
r1r2=127
r2=27r1
Rate will increase 27 times.

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