For the reaction, A(g)+2B(g)⇌2C(g), the rate constants for the forward and the reverse reactions are 1×10−4 and 2.5×10−2 respectively. The value of equilibrium constant, K for the reaction would be-
A
1×10−4
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B
2.5×10−2
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C
4×10−3
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D
2.5×102
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Solution
The correct option is C4×10−3 The equilibrium reaction is A(g)+2B(g)⇌2C(g). The expression for the equilibrium constant is K=kfkb. Substitute values in the above expression. K=1×10−42.5×10−2=4×10−3.