You visited us 1 times! Enjoying our articles? Unlock Full Access!

Derivation of Kp and Kc

For the react...

Question

For the reaction
$A (g) + B (g) ⇌ 2 C (g)$
The equilibrium concentration of A and B each is $0.2 m o l L^{- 1}$ and concentration of C is observed as $0.60 m o l L^{- 1}$ Equilibrium constant $K_{c}$ will be :

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 9
Since equilibrium concentrations are given:
$A + B ⇌ 2 C 0.2 0.2 0.6 K_{c} = \frac{[C]^{2}}{[A] [B]} putting the values, K_{c} = \frac{[0.6]^{2}}{[0.2] \times [0.2]} = 9 K_{c} = 9$

Suggest Corrections

Similar questions

A (g) + B (g) ⇌ 2 C (g)

0.2 m o l L^{- 1}

0.60 m o l L^{- 1}

K_{c}

A (g) + B (g) ⇌ 2 C (g)

0.2 m o l L^{- 1}

0.60 m o l L^{- 1}

K_{c}

A (g) + 2 B (g) ⇌ C (g)

A = 0.06 m o l L^{- 1}; B = 0.12 m o l L^{- 1}

C = 0.216 m o l L^{- 1}

K_{e q}

K_{c}

S O_{2} (g) + N O_{2} (g) ⇌ S O_{3} (g) + N O (g) .

N O_{2}

A_{(g)} + 2 B_{(} g) ⇌ C_{(g)}

A = 0.06 m o l L^{- 1}

B = 0.12 m o l L^{- 1}

C = 0.216 m o l L^{- 1}

K_{c}

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program