For the reaction A l - 2 B g - U -2-1 kcal - - S -20 cal - K at 300 KHence - G in k cal is

Δ H=Δ U + Δ n_gRT Δ H=2100+(2 × 2 × 300) nbsp; nbsp; (R=2calK^ 1mol^ 1) =3300 cal Δ G=Δ H TΔ S Δ G=3300 (300× 20)= 2700 cal= 2.70 kcal ...

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Gibbs Free Energy & Spontaneity

For the react...

Question

For the reaction
$A_{(l)} \to 2 B_{(g)}$
$Δ U = 2.1 kcal, Δ S = 20 cal/K$ at 300 K
Hence $Δ G$ in $k c a l$ is

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