Question

For the reaction, $A_{\left(g\right)}+2B_{\left(g\right)}\rightleftharpoons 3C\left(g\right)+D\left(g\right)$; $K_p=0.05$ atm at 1000K. The value of $K_c$ is represented by:

• A. $5\times {10}^{-4}R$
• B. $\frac{5\times {10}^{-4}}{R}$
• C. $5\times {10}^{-5}R$
• D. $\frac{5\times {10}^{-5}}{R}$

Answer 1

The correct option is D $\frac{5\times {10}^{-5}}{R}$

The given reaction is :-

$A_{\left(g\right)}+2B_{\left(g\right)}\rightleftharpoons 3C_{\left(g\right)}+O_{\left(g\right)};K_P=0.05atm$

Now, $K_P=K_C{\left(RT\right)}^{△n}$

$△n=$ No. of moles of gaseous (products - reactants)

$=3+1-2-1=1$

So, $K_P=K_C\left(RT\right)$

$\Rightarrow K_C=\frac{K_P}{RT}=\frac{0.05}{R\times 1000}=\frac{5\times {10}^{-5}}{R}$