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Entropy Change in Isothermal Process

For the react...

Question

For the reaction:
$A (s) ⟶ B (s) + C (s) J K^{- 1} {m o l}^{- 1}$
Calculate the entropy change at $298 K$ and $1$ atm if absolute entropies (in $J K^{- 1} {m o l}^{- 1}$ ) are:
$A = 130, B = 203, C = 152$

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Solution

$Δ S^{o} = \sum S_{(p r o d u c t s)}^{o} - \sum S_{r e a c t a n t s}^{o} = [S_{B}^{o} + S_{C}^{o}] - [S_{A}^{o}]$
$= [203 + 152] - [130]$
$= 225 J K^{- 1}$

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