The temperature at which the rate constant of the reaction is
10−4 s−1 is ________ K. (Rounded off to the nearest integer)
[Given: The rate constant of the reaction is 10−5 s−1 at 500 K.]
From Arrhenius equation,
log10K=log10A−Ea2.303RT
Slope=−Ea2.303R=−10000
log10K1K2=−Ea2.303R(1T1−1T2)
log1010−410−5=−10000(1T−1500)
1=10000(1500−1T)
110000=1500−1T
1T=1500−110000
1T=20−110000=1910000
T=1000019
∴ T=526 K