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Question

For the reaction, aA+bBcC+dD, the plot of logK vs 1/T is given below:

The temperature at which the rate constant of the reaction is
104 s1 is ________ K. (Rounded off to the nearest integer)

[Given: The rate constant of the reaction is 105 s1 at 500 K.]


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Solution

From Arrhenius equation,
log10K=log10AEa2.303RT

Slope=Ea2.303R=10000

log10K1K2=Ea2.303R(1T11T2)

log10104105=10000(1T1500)

1=10000(15001T)

110000=15001T

1T=1500110000

1T=20110000=1910000

T=1000019

T=526 K


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