Question

For the reaction,

${AB}_2\left(g\right)\rightleftharpoons AB\left(g\right)+B\left(g\right)$

If $\alpha$ is negligible, then degree of dissociation ($\alpha$) of ${AB}_2$ is proportional to:

• A. $\frac{1}{P}$
• B. $\frac{1}{V}$
• C. $\frac{1}{\sqrt{P}}$
• D. $\sqrt{V}$

Answer 1

Answer: (C), (D)

The correct options are
C $\frac{1}{\sqrt{P}}$
D $\sqrt{V}$

For reaction:
${AB}_2\left(g\right)\rightleftharpoons AB\left(g\right)+B\left(g\right)$

At eq. $1-\alpha$ $\alpha$ $\alpha$

$K=\frac{\frac{\alpha }{V}\times \frac{\alpha }{V}}{\frac{1-\alpha }{V}}=\frac{{\alpha }^2}{V}$ as $\alpha \ll 1$

Degree of dissociation, ($\alpha$) $=\sqrt{KV}$

$=\sqrt{\frac{K}{P}}$ as $PV=nRT$

Hence, option C and D are correct.