Question

For the reaction, $AB\left(g\right)\rightleftharpoons A\left(g\right)+B\left(g\right)$, $AB$ is $33\%$ dissociated at total pressure of $P$. Therefore, $P$ is related to $K_P$ as $P=x{K}_P$. Find out the value of $x$.

Answer 1

$AB\left(g\right)\rightleftharpoons A\left(g\right)+B\left(g\right)$
$t_0:100$
$t_{eq}:1-\frac{1}{3}\frac{1}{3}\frac{1}{3}$

$P_{AB}=\frac{\frac{2}{3}}{\frac{4}{3}}\times p=\frac{p}{2}$
$P_A=P_B=\frac{\frac{1}{3}}{\frac{4}{3}}\times p=\frac{p}{4}$
$K_P=\frac{\frac{p}{4}\times \frac{p}{4}}{\frac{p}{2}}=\frac{p}{8}$
$p=8K_P$