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Question

For the reaction Ag+(aq)+Cl(aq)AgCl(s); the ΔGo values for Ag+(aq),Cl(aq) and AgCl(s) are + 77, -129 and -109 kJ mol1. Write the cell representation of above reaction and calculate Ksp of AgCl at 298 K.
(Multiply the ans by 1010)

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Solution

ΔG=ΔG(AgCl(s))[ΔG(Ag+)+ΔG(Cl)]=109kJ/mol[77kJ/mol129kJ/mol]=57kJ/mol
ΔG=nFE
E=ΔGnF=57000J/mol1×96500=0.591V
E0=0.222V
E=E00.0592nlog1[Ag+][Cl]
0.59V=0.222V0.05921log1Ksp
log1Ksp=6.2276
1Ksp=1.688×106
Ksp=5.9×107
The molar mass of AgCl is 143.5 g/mol.
Ksp=5.9×107143.5=4×109
Hence, Ksp×101040

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