For the reaction Ag+(aq)+Cl−(aq)⇌AgCl(s); the ΔGo values for Ag+(aq),Cl−(aq) and AgCl(s) are + 77, -129 and -109 kJ mol−1. Write the cell representation of above reaction and calculate Ksp of AgCl at 298 K. (Multiply the ans by 1010)
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Solution
ΔG=ΔG(AgCl(s))−[ΔG(Ag+)+ΔG(Cl−)]=−109kJ/mol−[77kJ/mol−129kJ/mol]=−57kJ/mol ΔG=−nFE E=−ΔGnF=−57000J/mol1×96500=0.591V E0=0.222V E=E0−0.0592nlog1[Ag+][Cl−] 0.59V=0.222V−0.05921log1Ksp log1Ksp=6.2276 1Ksp=1.688×106 Ksp=5.9×10−7 The molar mass of AgCl is 143.5 g/mol. Ksp=5.9×10−7143.5=4×10−9 Hence, Ksp×1010≃40