For the reaction at $300 K$ , $A (g) ⇌ V (g) + S (g)$
$△_{r} H^{o} = - 30 k J / m o l, △_{r} S^{o} = - 0.1 k J K^{- 1} . m o l^{- 1}$
What is the value of equilibrium constant?

0

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1

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10

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+ R T

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Solution

The correct option is B $1$
The given reaction is $A (g) ⇌ V (g) + S (g)$
$△_{r} H^{o} = - 30 k J / m o l, △_{r} S^{o} = - 0.1 k J K^{- 1} . m o l^{- 1}$
We know the relation
$△_{r} G^{o} = △_{r} H^{o} - T \cdot △_{r} S^{o}$
$△_{r} G^{o} = - 30 + 300 \times 0.1 = 0$
Also, at equilibrium
$△_{r} G^{o} = - 2.303 R T l o g K_{e q b} = 0$
$K_{e q b} = 1$

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